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Grep pattern one match per input
Grep pattern one match per input















We know the length of the string and the input line. I was hoping for a piped one-liner matches="$(|grep )" Instead grep -q exits as soon as the pattern matches and the exit-status of grep is used in the if statement to determine what branch to take ( echo no or echo yes. 1 01-12-2012 stumpyuk Registered User 21, 0 grep - match files containing minimum number of pattern matches I want to search a bunch of files and list only those containing a minimum number of pattern matches. This does not actually extract the lines that matches the expression. I have to persist the command output and fire off potentially two greps. /mazegen 5 7 grep -q ' ' then echo no else echo yes fi. By default, grep prints the matching lines. What I have works but seems inefficient and I suspect there is a better way. Grep searches one or more input files for lines containing a match to a specified pattern. Using a | (or) in the pattern doesn't do what I am after as it would return all lines with B. If my input string is 'Y' then I want to return XYZ If my input string is 'Z' then I want to return XYZ If my input string is 'C' then I want to return C1

Grep pattern one match per input series#

Grep also accepts inputs (usually via a pipe) from another command or series of commands. First, Grep can be used to search a given file or files on a system (including a recursive search through sub-folders).

grep pattern one match per input

If my input string is 'B' then I want to return B There are two ways to provide input to Grep, each with its own particular uses. grep searches the named input FILE s (or standard input if no files are named, or if a single hyphen-minus ( -) is given as file name) for lines containing a match to the given PATTERN. I am currently using grep -E but am open to awk or sed.Ĭonsider this output written to file: > cat command.out I want to run a particular command, check the output of that command for that input string, first returning lines that match on $ and only if that does not return any lines, then return all lines that contain anywhere in the line. I am writing a script that accepts as an argument a string.















Grep pattern one match per input